In a reaction,$5.3 \, g$ of sodium carbonate reacted with $6 \, g$ of acetic acid. The products were $2.2 \, g$ of carbon dioxide,$0.9 \, g$ of water,and $8.2 \, g$ of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
$\text{Sodium carbonate} + \text{Acetic acid} \to \text{Sodium acetate} + \text{Carbon dioxide} + \text{Water}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The Law of Conservation of Mass states that mass can neither be created nor destroyed during a chemical reaction.
This means that the total mass of the reactants must be equal to the total mass of the products.
Step $1$: Calculate the total mass of the reactants $(LHS)$:
$\text{Mass of reactants} = \text{Mass of sodium carbonate} + \text{Mass of acetic acid} = 5.3 \, g + 6 \, g = 11.3 \, g$.
Step $2$: Calculate the total mass of the products $(RHS)$:
$\text{Mass of products} = \text{Mass of sodium acetate} + \text{Mass of carbon dioxide} + \text{Mass of water} = 8.2 \, g + 2.2 \, g + 0.9 \, g = 11.3 \, g$.
Step $3$: Compare $LHS$ and $RHS$:
Since $LHS = RHS = 11.3 \, g$,the total mass remains conserved.
Therefore,these observations are in agreement with the law of conservation of mass.

Explore More

Similar Questions

Why is it not possible to see an atom with naked eyes?

Write the chemical formulae of the following:
$(i)$ Magnesium chloride
$(ii)$ Calcium oxide
$(iii)$ Copper nitrate
$(iv)$ Aluminium chloride
$(v)$ Calcium carbonate.

How many atoms are present in a $(i)$ $H_2S$ molecule and $(ii)$ $PO_4^{3-}$ ion?

Calculate the molecular masses of $H_2$,$O_2$ and $Cl_2$.

Write down the chemical formulae of:
$(i)$ Sodium oxide
$(ii)$ Aluminium chloride
$(iii)$ Sodium sulphide
$(iv)$ Magnesium hydroxide

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo