In a reaction of aniline,a coloured product C | vedclass

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(B) $1$. The reaction of aniline $(A)$ with $NaNO_2$ and $HCl$ at $0-5^{\circ}C$ (cold conditions) produces benzene diazonium chloride $(B)$.$2$. Benz

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(B) $1$. The reaction of aniline $(A)$ with $NaNO_2$ and $HCl$ at $0-5^{\circ}C$ (cold conditions) produces benzene diazonium chloride $(B)$.$2$. Benzene diazonium chloride $(B)$ undergoes an electrophilic aromatic substitution (coupling reaction) with $N,N$-dimethylaniline.$3$. The coupling occurs at the para-position of the $N,N$-dimethylaniline ring to form $p$-dimethylaminoazobenzene,which is a yellow-coloured dye known as 'Butter yellow' $(C)$.$4$. The structure of $C$ is $Ph-N=N-C_6H_4-N(CH_3)_2$.

In a reaction of aniline,a coloured product $C$ was obtained as shown below:
$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$
The structure of $C$ would be:

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In a reaction of aniline,a coloured product $C$ was obtained as shown below:$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$The structure of $C$ would be: