In a resonance tube of length 0.8 ,m, an air | vedclass

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(B) Given: Length of tube $L = 0.8 \,m$, Frequency $f = 375 \,Hz$, Speed of sound $v = 330 \,m/s$.For the fundamental frequency in a resonance tube (c

Vedclass · Accepted Answer

$0.58$

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(B) Given: Length of tube $L = 0.8 \,m$, Frequency $f = 375 \,Hz$, Speed of sound $v = 330 \,m/s$.For the fundamental frequency in a resonance tube (closed at one end), the length of the air column $\ell$ is given by $\ell = \frac{v}{4f}$.Substituting the values: $\ell = \frac{330}{4 	imes 375} = \frac{330}{1500} = 0.22 \,m$.This $\ell$ represents the length of the air column from the top.The water level from the bottom is the total length of the tube minus the length of the air column: $h = L - \ell$.$h = 0.8 \,m - 0.22 \,m = 0.58 \,m$.

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