(A) Total number of students in the row = $40$.Soman's position from the left end = $30^{th}$.Kailash is $6^{th}$ to the left of Soman.Therefore, Kail

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(A) Total number of students in the row = $40$.Soman's position from the left end = $30^{th}$.Kailash is $6^{th}$ to the left of Soman.Therefore, Kailash's position from the left end = $30 - 6 = 24^{th}$.To find Kailash's position from the right end, we use the formula: $\text{Position from right} = (\text{Total students} - \text{Position from left}) + 1$.Position from right = $(40 - 24) + 1 = 16 + 1 = 17^{th}$.

Competitive Reasoning Number, Ranking and Time Sequence Test Number, Ranking and Time Sequence Test

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In a row of $40$ students facing North, Kailash is $6^{th}$ to the left of Soman. If Soman is $30^{th}$ from the left end of the row, how far is Kailash from the right end of the row (in $^{th}$)?

A
$17$
B
$16$
C
$15$
D
$26$

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In a row of $40$ students facing North, Kailash is $6^{th}$ to the left of Soman. If Soman is $30^{th}$ from the left end of the row, how far is Kailash from the right end of the row (in $^{th}$)?

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