In a series $LCR$ resonance circuit,if we change the resistance only,from a lower to higher value:

If the inductance and capacitance are both doubled in an $L-C-R$ circuit,the resonant frequency of the circuit will

In a series $LCR$ resonant circuit, $R = 800 \text{ } \Omega$, $C = 2 \text{ } \mu\text{F}$ and the voltage across the resistance is $200 \text{ V}$. The angular frequency is $\omega = 250 \text{ rad/s}$. At resonance, what is the voltage across the capacitance (in $\text{ V}$)?

$A$ series $LCR$ circuit is connected to an ac voltage source. When $L$ is removed from the circuit,the phase difference between current and voltage is $\frac{\pi}{3}$. If instead $C$ is removed from the circuit,the phase difference is again $\frac{\pi}{3}$ between current and voltage. The power factor of the circuit is:

When resonance is produced in a series $LCR$ circuit,then which of the following is not correct?

In an $LCR$ circuit,the capacitance is changed from $C$ to $2C$. For the resonant frequency to remain unchanged,the inductance should be changed from $L$ to: