In a seconds pendulum,the mass of the bob is | vedclass

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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$.Here,$L$ is the length of the pendulum and $g$ is the a

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$2$

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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$.Here,$L$ is the length of the pendulum and $g$ is the acceleration due to gravity.The formula shows that the time period $T$ is independent of the mass of the bob.$A$ seconds pendulum is defined as a pendulum with a time period of $2\, \sec$.Since the mass does not affect the time period,replacing the $30\, g$ bob with a $90\, g$ bob will not change the time period.Therefore,the time period remains $2\, \sec$.

In a seconds pendulum,the mass of the bob is $30\, g$. If it is replaced by a $90\, g$ mass,then its time period will be ... $\sec$.

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