In a set of reactions,propionic acid yielded | vedclass

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(A) The reaction sequence is as follows:$1$. Propionic acid $(CH_3CH_2COOH)$ reacts with $SOCl_2$ to form propionyl chloride $(B = CH_3CH_2COCl)$.$2$.

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$CH_3CH_2NH_2$

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(A) The reaction sequence is as follows:$1$. Propionic acid $(CH_3CH_2COOH)$ reacts with $SOCl_2$ to form propionyl chloride $(B = CH_3CH_2COCl)$.$2$. Propionyl chloride reacts with $NH_3$ to form propionamide $(C = CH_3CH_2CONH_2)$.$3$. Propionamide reacts with $KOH$ and $Br_2$ (Hofmann bromamide degradation reaction) to form ethylamine $(D = CH_3CH_2NH_2)$.Thus,the structure of $D$ is $CH_3CH_2NH_2$.

In a set of reactions,propionic acid yielded a compound $D$.
$CH_3CH_2COOH$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{NH_3} C$ $\xrightarrow{KOH, Br_2} D$
The structure of $D$ would be

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In a set of reactions,propionic acid yielded a compound $D$.$CH_3CH_2COOH$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{NH_3} C$ $\xrightarrow{KOH, Br_2} D$The structure of $D$ would be