In a single throw of two dice,what is the pro | vedclass

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(A) When two dice are thrown,the possible outcomes for each die range from $1$ to $6$.The maximum possible sum of the numbers on the two dice is $6 +

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) When two dice are thrown,the possible outcomes for each die range from $1$ to $6$.The maximum possible sum of the numbers on the two dice is $6 + 6 = 12$.Since the sum $13$ is greater than the maximum possible sum of $12$,it is impossible to obtain a total of $13$.Therefore,the number of favorable outcomes is $0$.The probability is given by the formula: $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of possible outcomes}}$.$P(13) = \frac{0}{36} = 0$.

In a single throw of two dice,what is the probability of getting a total of $13$?

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