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(B) In a standing wave,all particles of the medium between two consecutive nodes vibrate in phase. This means they all pass through their respective m

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Different speeds at same instant

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(B) In a standing wave,all particles of the medium between two consecutive nodes vibrate in phase. This means they all pass through their respective mean positions at the same instant of time. The displacement of a particle in a standing wave is given by $y = A(x) \sin(\omega t + \phi)$,where $A(x)$ is the amplitude which depends on the position $x$. The velocity of a particle is given by $v = \frac{dy}{dt} = A(x) \omega \cos(\omega t + \phi)$. At the mean position,$\sin(\omega t + \phi) = 0$,which implies $\cos(\omega t + \phi) = \pm 1$. Thus,the speed at the mean position is $|v| = A(x) \omega$. Since the amplitude $A(x)$ varies with the position $x$,the particles have different speeds at the same instant when they cross the mean position.

In a standing wave,all particles of the medium cross the mean position with

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