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(A) According to the first law of thermodynamics,$dQ = dU + dW$,where $dQ$ is the heat supplied to the system,$dU$ is the change in internal energy,an

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$18$

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(A) According to the first law of thermodynamics,$dQ = dU + dW$,where $dQ$ is the heat supplied to the system,$dU$ is the change in internal energy,and $dW$ is the work done by the system.Given:Heat released by the gas,$dQ = -20 \ J$ (negative because heat is released).Work done on the gas,$dW = -8 \ J$ (negative because work is done on the system).Initial internal energy,$U_i = 30 \ J$.Using the formula $dQ = (U_f - U_i) + dW$:$-20 = (U_f - 30) + (-8)$$-20 = U_f - 30 - 8$$-20 = U_f - 38$$U_f = 38 - 20$$U_f = 18 \ J$.Therefore,the final internal energy is $18 \ J$.

In a thermodynamics process,the pressure of a fixed mass of a gas is changed in such a manner that the gas releases $20 \ J$ of heat and $8 \ J$ of work is done on the gas. If the initial internal energy of the gas was $30 \ J$,what will be the final internal energy in $J$?

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