In a touring cricket team,there are 16 player | vedclass

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(B) Total players = $16$.Number of bowlers = $5$.Number of wicket-keepers = $2$.Remaining players (batsmen/all-rounders) = $16 - (5 + 2) = 9$.We need

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$720$

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(B) Total players = $16$.Number of bowlers = $5$.Number of wicket-keepers = $2$.Remaining players (batsmen/all-rounders) = $16 - (5 + 2) = 9$.We need to select a team of $11$ players including $3$ bowlers,$1$ wicket-keeper,and the remaining $11 - (3 + 1) = 7$ players from the remaining $9$ players.The number of ways to select the team is given by:$= ^5C_3 	imes ^2C_1 	imes ^9C_7$$= \frac{5 	imes 4}{2 	imes 1} 	imes 2 	imes \frac{9 	imes 8}{2 	imes 1}$$= 10 	imes 2 	imes 36 = 720$.

In a touring cricket team,there are $16$ players in all,including $5$ bowlers and $2$ wicket-keepers. How many teams of $11$ players can be chosen from these,such that each team includes exactly $3$ bowlers and $1$ wicket-keeper?

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