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(A) Given:Increase in base current, $\Delta I_b = 50 \mu A = 50 	imes 10^{-6} \ A$.Increase in collector current, $\Delta I_c = 1 \ mA = 1 	imes 10^

Vedclass · Accepted Answer

$20$

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(A) Given:Increase in base current, $\Delta I_b = 50 \mu A = 50 	imes 10^{-6} \ A$.Increase in collector current, $\Delta I_c = 1 \ mA = 1 	imes 10^{-3} \ A$.The collector voltage is kept constant, which is the condition for calculating the common-emitter current gain $\beta$.The current gain $\beta$ is defined as the ratio of the change in collector current to the change in base current:$\beta = \frac{\Delta I_c}{\Delta I_b}$Substituting the values:$\beta = \frac{1 	imes 10^{-3} \ A}{50 	imes 10^{-6} \ A}$$\beta = \frac{1000}{50} = 20$.Therefore, the current gain of the transistor is $20$.

In a transistor circuit, when the base current is increased by $50 \mu A$ keeping the collector voltage fixed at $2 \ V$, the collector current increases by $1 \ mA$. The current gain of the transistor is

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