In a transistor,when the emitter current changes by $9.85 \,mA$,the collector current changes by $9.5 \,mA$. Then the base current is (in $\,mA$)

In a transistor,the collector current is always less than the emitter current because:

The transfer characteristics [output voltage $(V_o)$ vs input voltage $(V_i)$] for a base-biased transistor in $CE$ configuration are shown in the figure. For using a transistor as a switch,it is used:

The phase difference between input and output voltages of a $CE$ (common emitter) amplifier circuit is........$^o$.

In a junction transistor, the collector current changes by $6.8 \,mA$, if the emitter current is changed by $7 \,mA$. For such a transistor, the current amplification factor is

In a properly biased transistor: