In a triangle ABC,AB + BC = 12 text{ cm},BC + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given:$AB + BC = 12 	ext{ cm}$$BC + CA = 14 	ext{ cm}$$CA + AB = 18 	ext{ cm}$Adding these three equations:$(AB + BC) + (BC + CA) + (CA + AB) =

Vedclass · Accepted Answer

$\frac{7}{2}$

Vedclass · Answer

(B) Given:$AB + BC = 12 	ext{ cm}$$BC + CA = 14 	ext{ cm}$$CA + AB = 18 	ext{ cm}$Adding these three equations:$(AB + BC) + (BC + CA) + (CA + AB) = 12 + 14 + 18$$2(AB + BC + CA) = 44$$AB + BC + CA = 22 	ext{ cm}$The perimeter of the triangle is $22 	ext{ cm}$.Let $r$ be the radius of the circle. The perimeter (circumference) of the circle is $2 \pi r$.According to the problem,the perimeter of the circle is equal to the perimeter of the triangle:$2 \pi r = 22$$2 	imes \frac{22}{7} 	imes r = 22$$r = \frac{22 	imes 7}{2 	imes 22}$$r = \frac{7}{2} 	ext{ cm}$

In a triangle $ABC$,$AB + BC = 12 \text{ cm}$,$BC + CA = 14 \text{ cm}$,and $CA + AB = 18 \text{ cm}$. Find the radius of the circle (in $\text{cm}$) which has the same perimeter as the triangle.

Similar Questions

The circumference of two circles is $88 \text{ m}$ and $220 \text{ m}$ respectively. What is the difference between the area of the larger circle and that of the smaller circle (in $m^2$)?

The dimensions of the floor of a rectangular hall are $4\, m \times 3\, m$. The floor of the hall is to be tiled fully with $8\, cm \times 6\, cm$ rectangular tiles without breaking the tiles into smaller sizes. The number of tiles required is:

$A$ wire is in the form of a semi-circle of $7 \, cm$ radius. The length of the wire will be (in $cm$):

The area of a sector of a circle of radius $5 \, cm$,formed by an arc of length $3.5 \, cm$,is ..... $cm^2$.

If the area of a square is $50$ $sq$ units,then the area of the circle drawn on its diagonal is

Vedclass Test Series

Exam Paper Generator

Online Exam Module