(C) Given in $\triangle ABC$: $a=3, b=4$ and $\sin A = \frac{3}{4}$.Using the Sine Rule: $\frac{\sin A}{a} = \frac{\sin B}{b}$.Substituting the values

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(C) Given in $\triangle ABC$: $a=3, b=4$ and $\sin A = \frac{3}{4}$.Using the Sine Rule: $\frac{\sin A}{a} = \frac{\sin B}{b}$.Substituting the values: $\frac{\frac{3}{4}}{3} = \frac{\sin B}{4}$.$\Rightarrow \frac{3}{4 \times 3} = \frac{\sin B}{4}$.$\Rightarrow \frac{1}{4} = \frac{\sin B}{4}$.$\Rightarrow \sin B = 1$.Since $\sin B = 1$, we have $B = 90^{\circ}$.Therefore, $\angle CBA = 90^{\circ}$.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

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In a triangle $ABC$, if $a=3, b=4$ and $\sin A=\frac{3}{4}$, then $\angle CBA = (\text{in } ^{\circ})?$

AP EAMCET 2021 All AP EAMCET

A
$60$
B
$75$
C
$90$
D
$45$

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In a triangle $ABC$, if $a=3, b=4$ and $\sin A=\frac{3}{4}$, then $\angle CBA = (\text{in } ^{\circ})?$

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