In a vibrating string with fixed ends,the waves are of type:

$A$ string is rigidly tied at two ends and its equation of vibration is given by $y = \sin(2\pi x) \cos(2\pi t)$. Then the minimum length of the string is .... $m$

$A$ standing wave having $3$ nodes and $2$ antinodes is formed between two atoms having a distance of $1.21 \; \mathring{A}$ between them. The wavelength of the standing wave is .... $\mathring{A}$

Two waves of same frequency $(n)$ approaching each other with same velocity of $18\text{ m/s}$ interfere. The distance between two consecutive antinodes is

Give the distance between consecutive nodes and antinodes in terms of wavelength $\lambda$.

The vibration of a string fixed at both ends is described by $Y = 2 \sin(\pi x) \sin(100\pi t)$,where $Y$ is in $mm$,$x$ is in $cm$,and $t$ is in $sec$. Then: