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(A) For a wire of radius $R$ carrying a current $I$ uniformly distributed,the magnetic field $B$ at a distance $r$ from the centre (where $r < R$) is

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$100$

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(A) For a wire of radius $R$ carrying a current $I$ uniformly distributed,the magnetic field $B$ at a distance $r$ from the centre (where $r Given values: $I = 2 \ A$,$R = 1 \ mm = 10^{-3} \ m$,$r = 0.25 \ mm = 0.25 	imes 10^{-3} \ m$.Substituting these values into the formula:$B = \frac{(4 \pi 	imes 10^{-7}) 	imes 2 	imes (0.25 	imes 10^{-3})}{2 \pi 	imes (10^{-3})^2}$$B = \frac{2 	imes 10^{-7} 	imes 2 	imes 0.25 	imes 10^{-3}}{10^{-6}}$$B = \frac{10^{-10}}{10^{-6}} = 10^{-4} \ T$Since $1 \ T = 10^6 \ \mu T$,we have $B = 10^{-4} 	imes 10^6 \ \mu T = 100 \ \mu T$.

In a wire of radius $1 \ mm$,a steady current of $2 \ A$ uniformly distributed across the cross-section of the wire is flowing. Then the magnetic field at a point $0.25 \ mm$ from the centre of the wire is (in $\mu T$)

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