In a Young's double slit experiment,the dista | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The angular width of the central maximum in a single slit diffraction pattern is given by $	heta = \frac{2 \lambda}{b}$,where $b$ is the slit wid

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) The angular width of the central maximum in a single slit diffraction pattern is given by $	heta = \frac{2 \lambda}{b}$,where $b$ is the slit width.The angular separation between consecutive interference maxima in a Young's double slit experiment is $\Delta 	heta = \frac{\lambda}{d}$,where $d$ is the distance between the slits.The number of interference maxima $n$ that fit within the central diffraction maximum is given by the ratio of the angular width of the central diffraction maximum to the angular separation of the interference fringes:$n = \frac{2 \lambda / b}{\lambda / d} = \frac{2d}{b}$.Given that $d = 6.1b$,we substitute this into the equation:$n = \frac{2 	imes (6.1b)}{b} = 12.2$.Since the number of maxima must be an integer,we consider the maxima that lie strictly within the central diffraction envelope. Thus,$12$ intensity maxima are observed.

In a Young's double slit experiment,the distance between the two identical slits is $6.1$ times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is

Similar Questions

In which of the following is the interference due to the division of wave front?

In Young's double-slit experiment,the value of $\lambda = 500\, nm$. The value of $d = 1\, mm$ and $D = 1\, m$. Then the minimum distance from the central maximum for which the intensity is half the maximum intensity will be:

Young's double-slit experiment is performed in air and then performed in water. How does the fringe width change?

The distance between two slits in a double slit experiment is $1 \ mm$. The distance between the slits and the screen is $1 \ m$. If the distance of the $10^{th}$ fringe from the central fringe is $5 \ mm$, then the wavelength of light is $... \mathring{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module