In a Young's double slit experiment,the separation between the slits is $0.15 \; mm$. In the experiment,a source of light of wavelength $589 \; nm$ is used and the interference pattern is observed on a screen kept $1.5 \; m$ away. The separation between the successive bright fringes on the screen is $...... \; mm$. (in $.9$)

If the source of light used in a Young's Double Slit Experiment is changed from red to blue,then

Two parallel slits $0.6 \,mm$ apart are illuminated by a light source of wavelength $6000 \,\mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \,m$ away from the slits is:

$A$ Young's double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is

In Young's double-slit experiment,if the distance between the slits is twice the wavelength,the number of possible interference maxima is:

In a Young's double slit experiment,the source $S$ and the two slits $A$ and $B$ are vertical,with slit $A$ above slit $B$. The fringes are observed on a vertical screen $K$. The optical path length from $S$ to $B$ is increased very slightly (by introducing a transparent material of higher refractive index) and the optical path length from $S$ to $A$ is not changed. As a result,the fringe system on $K$ moves: