In a Young's double slit experiment, the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Slit separation $d = 0.2 	ext{ mm} = 2 	imes 10^{-4} 	ext{ m}$.
Distance to screen $D = 2.0 	ext{ m}$.
Order of fringe $n = 3$.
Dist

Vedclass · Accepted Answer

$5000 \mathring{A}$

Vedclass · Answer

(B) Given: Slit separation $d = 0.2 	ext{ mm} = 2 	imes 10^{-4} 	ext{ m}$.
Distance to screen $D = 2.0 	ext{ m}$.
Order of fringe $n = 3$.
Distance of $n^{th}$ bright fringe $y_n = 1.5 	ext{ cm} = 1.5 	imes 10^{-2} 	ext{ m}$.
The formula for the position of the $n^{th}$ bright fringe is $y_n = \frac{n \lambda D}{d}$.
Rearranging for wavelength $\lambda$: $\lambda = \frac{y_n d}{n D}$.
Substituting the values: $\lambda = \frac{1.5 	imes 10^{-2} 	imes 2 	imes 10^{-4}}{3 	imes 2.0}$.
$\lambda = \frac{3 	imes 10^{-6}}{6} = 0.5 	imes 10^{-6} 	ext{ m}$.
Converting to $ \mathring{A}$s: $\lambda = 0.5 	imes 10^{-6} 	imes 10^{10} \mathring{A} = 5000 \mathring{A}$.
Thus, the wavelength of light used is $5000 \mathring{A}$.

In a Young's double slit experiment, the slits are separated by $0.2 \text{ mm}$ and the screen is placed $2.0 \text{ m}$ away. The distance between the central bright fringe and the third bright fringe is measured to be $1.5 \text{ cm}$. Determine the wavelength of light used in the experiment.

Similar Questions

The wavelength of light $500 \, nm$ is used in a Young's double slit experiment. The distance between the slits and the screen is $100 \, cm$ and the slits are separated by $1 \, mm$. Find the distance between the fifth $(5^{th})$ and third $(3^{rd})$ bright fringes. (in $mm$)

Young's double-slit experiment is performed with a wavelength of $550 \,nm$. If the distance between the two slits is $1.10 \,mm$ and the distance between the screen and the slits is $1 \,m$,then the distance between two consecutive bright or dark fringes is .....$mm$.

In Young's double slit experiment, in an interference pattern, a minimum is observed exactly in front of one slit. The distance between the two coherent sources is $d$ and $D$ is the distance between the source and the screen. The possible wavelengths used are inversely proportional to

In a Young's double-slit experiment,the slit separation is $0.589 \, mm$ using sodium light. What is the angular separation between the third maximum and the central maximum? $(\lambda = 589 \, nm)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module