In the reaction of 1-vinyl--2-bromoethylbenze | vedclass

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Question

(C) The reaction involves the electrophilic addition of $HBr$ to the vinyl group $(-CH=CH_2)$ attached to the benzene ring. According to Markovnikov's

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Vedclass · Answer

(C) The reaction involves the electrophilic addition of $HBr$ to the vinyl group $(-CH=CH_2)$ attached to the benzene ring. According to Markovnikov's rule,the proton $(H^+)$ adds to the carbon with more hydrogen atoms,forming a more stable carbocation. The vinyl group $-CH=CH_2$ becomes $-CH^+-CH_3$ (a secondary benzylic carbocation),which is stabilized by resonance with the benzene ring. Then,the bromide ion $(Br^-)$ attacks this carbocation to form the final product. Comparing the options,the structure in option $C$ represents the addition of $HBr$ across the double bond following Markovnikov's rule,resulting in the formation of a $1$-bromoethyl group.

In the reaction of $1$-vinyl-$-2$-bromoethylbenzene with $HBr$,the major product is:

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