In acidic medium,H_2O_2 changes Cr_2O_7^{2-} | vedclass

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Question

(C) The structure of $CrO_5$ (butterfly structure) contains one double-bonded oxygen atom (oxidation state $-2$) and four oxygen atoms involved in two

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The structure of $CrO_5$ (butterfly structure) contains one double-bonded oxygen atom (oxidation state $-2$) and four oxygen atoms involved in two peroxy linkages (each oxygen atom in a peroxy linkage has an oxidation state of $-1$).Let the oxidation state of $Cr$ be $x$.$x + 1(-2) + 4(-1) = 0$$x - 2 - 4 = 0$$x - 6 = 0$$x = +6$Therefore,the oxidation state of $Cr$ in $CrO_5$ is $+6$.

In acidic medium,$H_2O_2$ changes $Cr_2O_7^{2-}$ to $CrO_5$ which has two peroxy linkages. The oxidation state of $Cr$ in $CrO_5$ is

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