In allene $(C_3H_4)$,the type$(s)$ of hybridisation of the carbon atoms is (are):

  • A
    $sp$ and $sp^3$
  • B
    $sp$ and $sp^2$
  • C
    only $sp^3$
  • D
    $sp^2$ and $sp^3$

Explore More

Similar Questions

$XeF_4$ is square planar whereas $CCl_4$ is tetrahedral because

The ammonium ion $(NH_4^+)$ is:

The central atom in a molecule is in $sp^2$ hybrid state. The shape of the molecule will be

Among $[I_3]^{+}$,$[SiO_4]^{4-}$,$SO_2Cl_2$,$XeF_2$,$SF_4$,$ClF_3$,$Ni(CO)_4$,$XeO_2F_2$,$[PtCl_4]^{2-}$,$XeF_4$,and $SOCl_2$,the total number of species having $sp^3$ hybridised central atom is. . . . .

In which of the following compounds will the angle between two covalent bonds be the largest?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo