In alternating current circuits,the $a.c.$ meters measure

$A$ periodic voltage $V$ varies with time $t$ as shown in the figure. $T$ is the time period. The $r.m.s.$ value of the voltage is:

If the rms current in a $50 \text{ Hz}$ $AC$ circuit is $5 \text{ A}$,and at time $t=0$,the current $I$ is $0$. The value of current $I$ at $t=\frac{1}{300} \text{ s}$ is . . . . . . $A$.

An alternating e.m.f. is $e = e_0 \sin \omega t$. In what time will the e.m.f. reach half its maximum value,if $e$ starts from zero? ($T$ = time period)

What is the $r.m.s.$ value of the current $i = t^2$ for the time interval $0 < t < T$?

Define the root mean square (rms) value of an alternating current and provide its formula. Also,show the relationship between the rms current and the peak current on a graph of current versus $\omega t$.