In an $LCR$ circuit shown in the following figure,what will be the readings of the voltmeter across the resistor and ammeter if an $a.c.$ source of $220\,V$ and $100\,Hz$ is connected to it as shown?

$A$ circuit has a resistance of $11\,\Omega$,an inductive reactance of $25\,\Omega$,and a capacitive reactance of $18\,\Omega$. It is connected to an $AC$ source of $260\,V$ and $50\,Hz$. The current through the circuit (in amperes) is:

An $LCR$ series circuit with a resistance of $100 \, \Omega$ is connected to an $ac$ source of $200 \, V \, (r.m.s.)$ and angular frequency $300 \, rad/s$. When only the capacitor is removed, the current lags behind the voltage by $60^o$. When only the inductor is removed, the current leads the voltage by $60^o$. The average power dissipated is.....$W$

In the given circuit,the $AC$ source has $\omega = 100 \ rad/s$. Considering the inductor and capacitor to be ideal,the correct choice$(s)$ is(are):
$(A)$ The current through the circuit,$I$ is $0.3 \ A$
$(B)$ The current through the circuit,$I$ is $0.3 \sqrt{2} \ A$
$(C)$ The voltage across $100 \ \Omega$ resistor $= 10 \sqrt{2} \ V$
$(D)$ The voltage across $50 \ \Omega$ resistor $= 10 \sqrt{2} \ V$

The figure shows a combination of inductances and capacitances. The resonant frequency of the $L-C$ circuit is:

$A$ series $LCR$ circuit has $R=200 \Omega$, $L=663 \text{ mH}$, and $C=26.5 \mu F$. The applied alternating voltage has an amplitude of $50 \text{ V}$ and a frequency of $60 \text{ Hz}$ such that $X_{L}=250 \Omega$ and $X_{C}=100 \Omega$. The peak current is: (in $\text{ A}$)