In an $n-p-n$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$. If $2\%$ of the electrons are lost in the base,the current amplification factor $\beta$ is:

  • A
    $0.02$
  • B
    $7$
  • C
    $33$
  • D
    $49$

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$(2)$ The base-emitter junction is reverse-biased.
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