In an $n-p-n$ transistor,in $CE$ configuration:

In an $NPN$ transistor circuit,the collector current is $10 \,mA$. If $90\%$ of the electrons emitted reach the collector,the emitter current $(i_E)$ and base current $(i_B)$ are given by

The collector current in a common base amplifier using $n-p-n$ transistor is $24\; mA$. If $80\%$ of the electrons released by the emitter are accepted by the collector,then the base current is numerically

The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios. Then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \cdot \beta_{dc}}$ is

An $n-p-n$ transistor power amplifier in $C-E$ configuration gives