In an a.c. circuit with pure capacitance $C$ and a.c. source $E = E_0 \sin \omega t$, the equation of instantaneous current is given by

  • A
    $I = E_0 \omega C \sin(\omega t)$
  • B
    $I = E_0 \omega C \sin(\omega t + \pi/2)$
  • C
    $I = \frac{E_0}{\omega C} \sin(\omega t)$
  • D
    $I = \frac{E_0}{\omega C} \sin(\omega t + \pi/2)$

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