In an AC circuit,the peak value of voltage is | vedclass

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(C) The effective voltage (also known as the root mean square voltage,$V_{rms}$) is related to the peak voltage $(V_0)$ by the formula: $V_{rms} = \fr

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$300$

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(C) The effective voltage (also known as the root mean square voltage,$V_{rms}$) is related to the peak voltage $(V_0)$ by the formula: $V_{rms} = \frac{V_0}{\sqrt{2}}$.Given that the peak voltage $V_0 = 423 \ V$.Substituting the value into the formula:$V_{rms} = \frac{423}{\sqrt{2}} \approx \frac{423}{1.414} \approx 299.15 \ V$.Rounding to the nearest whole number,we get $V_{rms} = 300 \ V$.Therefore,the correct option is $C$.

In an $AC$ circuit,the peak value of voltage is $423 \ V$. Its effective voltage is .......... $V$.

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