In an aqueous glucose solution,the mole fraction of water is $40$ times the mole fraction of glucose. What is the weight percentage $(w/w)$ of glucose in the solution?

The molarity of a $1 \ molal$ glucose solution having a density of $1.2 \ g/mL$ is: (in $M$)

$A$ solution of sodium sulphate contains $92 \ g$ of $Na^{+}$ ions per kilogram of water. The molality of $Na^{+}$ ions in that solution in $mol \ kg^{-1}$ is:

$63 \ g$ of a compound (Mol. Wt. $= 126$) was dissolved in $500 \ g$ of distilled water. The density of the resultant solution is $1.126 \ g / mL$. The molarity of the solution is: (in $M$)

What will be the molality of $10\%$ w/w aqueous solution of $NaOH$ (in $m$)? (Molecular mass of $NaOH = 40 \ g \ mol^{-1}$)

Calculate the molality of $1 \ L$ solution of $93 \ \%$ $H_2SO_4$ (weight/volume). The density of the solution is $1.84 \ g/mL$.