In an $E. coli$ strain,the $i$ gene gets mutated such that its product cannot bind the inducer molecule. If the growth medium is provided with lactose,what will be the outcome?

  • A
    $z, y, a$ genes will be transcribed
  • B
    $z, y, a$ genes will not be translated
  • C
    $RNA$ polymerase will bind the promoter region
  • D
    Only $z$ gene will get transcribed

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Similar Questions

Which of the following statements concerning the regulatory gene $(i)$,associated with the $lac$ operon are incorrect?
$(I.)$ $\text{mRNA}$ is transcribed from the $i$ gene whether lactose is present or not.
$(II.)$ $\text{mRNA}$ is transcribed from the $i$ gene only when the lactose is present.
$(III.)$ $\text{mRNA}$ is transcribed from the $i$ gene only when the lactose is not present.
$(IV.)$ Lactose inhibits the translation of $i$ gene $\text{mRNA}$.

Few genes are found in all types of cells of differentiated multicellular organisms of higher classes. These are called:

Jacob and Monod studied lactose metabolism in $E. coli$ and proposed the operon concept,which is applicable for:

Which of the following is required as inducer$(s)$ for the expression of $Lac$ operon?

The diagram below shows a diagrammatic sketch of the maturation of insulin. Select the correct set of names labeled $A, B, C$,and $D$.

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