In an electrical circuit,two resistors of 2,O | vedclass

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(C) Given: Resistors $R_1 = 2\,\Omega$ and $R_2 = 4\,\Omega$ are connected in series.Voltage $V = 6\,V$.Time $t = 5\,s$.Total resistance $R_{eq} = R_1

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$20$

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(C) Given: Resistors $R_1 = 2\,\Omega$ and $R_2 = 4\,\Omega$ are connected in series.Voltage $V = 6\,V$.Time $t = 5\,s$.Total resistance $R_{eq} = R_1 + R_2 = 2\,\Omega + 4\,\Omega = 6\,\Omega$.The current $I$ flowing through the circuit is $I = V / R_{eq} = 6\,V / 6\,\Omega = 1\,A$.Since the resistors are in series,the same current $I = 1\,A$ flows through the $4\,\Omega$ resistor.The heat dissipated $H$ is given by the formula $H = I^2 R t$.Substituting the values: $H = (1)^2 	imes 4 	imes 5 = 1 	imes 4 	imes 5 = 20\,J$.

In an electrical circuit,two resistors of $2\,\Omega$ and $4\,\Omega$ respectively are connected in series to a $6\,V$ battery. The heat dissipated by the $4\,\Omega$ resistor in $5\,s$ will be ........ $J$.

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