In an electron gun,the control grid is given a negative potential relative to the cathode in order to:
- ADecelerate electrons
- BRepel electrons and thus to control the number of electrons passing through it
- CSelect electrons of the same velocity and converge them along the axis
- DDecrease the kinetic energy of electrons
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Similar Questions
The plate current $i_p$ in a triode valve is given by $i_p = K(V_p + \mu V_g)^{3/2}$,where $i_p$ is in $mA$ and $V_p$ and $V_g$ are in $V$. If $r_p = 10^4 \, \Omega$ and $g_m = 5 \times 10^{-3} \, \text{mho}$,then for $i_p = 8 \, mA$ and $V_p = 300 \, V$,what are the values of $K$ and the grid cut-off voltage?
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View SolutionThe transconductance of a triode amplifier is $2.5 \, \text{mS}$ (milli-mho) and its plate resistance is $20 \, \text{k}\Omega$. If the voltage amplification is $10$, find the load resistance in $\text{k}\Omega$.
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View SolutionThe point representing the cut-off grid voltage on the mutual characteristic of a triode is:
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View SolutionBriefly describe the valve in electronics.
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View SolutionThe plate resistance of two triode valves is $2 \, k\Omega$ and $4 \, k\Omega$. The amplification factor of each valve is $40$. The ratio of voltage amplification,when used with a $4 \, k\Omega$ load resistance,will be:
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