In an electroplating experiment,m , g of silv | vedclass

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(B) According to Faraday's law of electrolysis,the mass of substance deposited $(m)$ is directly proportional to the quantity of electricity passed $(

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$m/2$

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(B) According to Faraday's law of electrolysis,the mass of substance deposited $(m)$ is directly proportional to the quantity of electricity passed $(Q = i 	imes t)$.So,$m \propto i 	imes t$.Given: $m_1 = m$,$i_1 = 4 \, A$,$t_1 = 2 \, min = 120 \, s$.For the second case: $i_2 = 6 \, A$,$t_2 = 40 \, s$.Using the ratio: $\frac{m_1}{m_2} = \frac{i_1 	imes t_1}{i_2 	imes t_2}$.$\frac{m}{m_2} = \frac{4 	imes 120}{6 	imes 40} = \frac{480}{240} = 2$.Therefore,$m_2 = \frac{m}{2}$.

In an electroplating experiment,$m \, g$ of silver is deposited when $4 \, A$ of current flows for $2 \, min$. The amount (in $g$) of silver deposited by $6 \, A$ of current for $40 \, s$ will be

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