In an inductor,the current I varies with time | vedclass

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(D) The current in the inductor is given by $I = 5 + 16t$.Taking the derivative with respect to time $t$,we get the rate of change of current: $\frac{

Vedclass · Accepted Answer

$3.125$

Vedclass · Answer

(D) The current in the inductor is given by $I = 5 + 16t$.Taking the derivative with respect to time $t$,we get the rate of change of current: $\frac{dI}{dt} = 16 \,A/s$.The induced emf $\varepsilon$ in an inductor is given by the formula $|\varepsilon| = L \left| \frac{dI}{dt} ight|$.Given that $\varepsilon = 5 \,mV = 5 	imes 10^{-3} \,V$.Substituting the values into the formula: $5 	imes 10^{-3} = L 	imes 16$.Solving for $L$: $L = \frac{5 	imes 10^{-3}}{16} = 0.3125 	imes 10^{-3} \,H$.To express this in the form $	imes 10^{-4} \,H$,we write $L = 3.125 	imes 10^{-4} \,H$.Therefore,the correct option is $D$.

In an inductor,the current $I$ varies with time $t$ as $I = 5 \,A + 16 \,(A/s) \,t$. If the induced emf in the inductor is $5 \,mV$,the self-inductance of the inductor is .............. $\times 10^{-4} \,H$.

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