In an optical fibre,the core and cladding are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an optical fibre,the acceptance angle $	heta_a$ is given by the formula: $\sin 	heta_a = \sqrt{\mu_1^2 - \mu_2^2}$,where $\mu_1$ is the refr

Vedclass · Accepted Answer

$0^{\circ}-30^{\circ}$

Vedclass · Answer

(C) For an optical fibre,the acceptance angle $	heta_a$ is given by the formula: $\sin 	heta_a = \sqrt{\mu_1^2 - \mu_2^2}$,where $\mu_1$ is the refractive index of the core and $\mu_2$ is the refractive index of the cladding,assuming the surrounding medium is air $(\mu_0 = 1)$.Given $\mu_1 = 1.5$ and $\mu_2 = 1.414$.Substituting the values: $\sin 	heta_a = \sqrt{(1.5)^2 - (1.414)^2}$.Since $(1.414)^2 \approx 2$,we have $\sin 	heta_a = \sqrt{2.25 - 2} = \sqrt{0.25} = 0.5$.Therefore,$	heta_a = \sin^{-1}(0.5) = 30^{\circ}$.This means the incident light must enter the fibre within an angle range of $0^{\circ}$ to $30^{\circ}$ with the axis to undergo total internal reflection.Hence,option $(C)$ is correct.

$(a)$ Placenta	$(i)$ Androgens
$(b)$ Zona pellucida	$(ii)$ Human Chorionic Gonadotropin $(hCG)$
$(c)$ Bulbourethral glands	$(iii)$ Layer of the ovum
$(d)$ Leydig cells	$(iv)$ Lubrication of the penis

In an optical fibre,the core and cladding are made with materials of refractive indices $1.5$ and $1.414$ respectively. To observe total internal reflection,what will be the range of the incident angle with the axis of the optical fibre?

Similar Questions

If $y=y(x)$ is the solution of the differential equation $\frac{5+e^x}{2+y} \cdot \frac{dy}{dx} + e^x = 0$ satisfying $y(0)=1$,then a value of $y(\log_e 13)$ is

$A$ uniform chain has a mass $m$ and length $l$. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is

Assertion $(A)$: $-NH_2$ group of aniline is ortho,para directing in electrophilic substitutions.
Reason $(R)$: $-NH_2$ group stabilises the arenium ion formed by the ortho,para attack of the electrophile.
The correct answer is

If $x = \log_{5}(1000)$ and $y = \log_{7}(2058)$,then:

Match the following columns and select the correct option:
$(a)$ Placenta $(i)$ Androgens
$(b)$ Zona pellucida $(ii)$ Human Chorionic Gonadotropin $(hCG)$
$(c)$ Bulbourethral glands $(iii)$ Layer of the ovum
$(d)$ Leydig cells $(iv)$ Lubrication of the penis

$(a)\quad (b)\quad (c)\quad (d)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module