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(B) According to the Bohr model,the electrostatic force $F$ between the nucleus and the electron is given by Coulomb's law: $F = \frac{1}{4\pi\epsilon

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$F \propto 1/n^4$

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(B) According to the Bohr model,the electrostatic force $F$ between the nucleus and the electron is given by Coulomb's law: $F = \frac{1}{4\pi\epsilon_0} \frac{Ze^2}{r^2}$.In the Bohr model,the radius of the $n^{th}$ orbit is given by $r_n \propto n^2$.Substituting this into the force equation: $F \propto \frac{1}{r_n^2} \propto \frac{1}{(n^2)^2} = \frac{1}{n^4}$.Therefore,the force on the electron depends on the principal quantum number as $F \propto 1/n^4$.

In the Bohr model of a hydrogen atom,the electrostatic force on the electron depends on the principal quantum number $n$ as:

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