In Calvin cycle,if one molecule of RuBP is ca | vedclass

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(A) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between one molecule of $RuBP$ ($5$-

Vedclass · Accepted Answer

$2$

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(A) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between one molecule of $RuBP$ ($5$-carbon sugar) and one molecule of $CO_2$.This reaction forms an unstable $6$-carbon intermediate,which immediately undergoes hydrolysis to produce $2$ molecules of $3$-phosphoglyceric acid ($PGA$,a $3$-carbon compound).Therefore,the carboxylation of one molecule of $RuBP$ results in the formation of $2$ molecules of $PGA$.

In Calvin cycle,if one molecule of $RuBP$ is carboxylated then how many $PGA$ molecules will be formed?

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