In the Carius method for the estimation of ha | vedclass

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(A) The percentage of bromine is calculated using the formula: $\% \ Br = \frac{	ext{Atomic mass of } Br}{	ext{Molar mass of } AgBr} 	imes \frac{

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$34.04$

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(A) The percentage of bromine is calculated using the formula: $\% \ Br = \frac{	ext{Atomic mass of } Br}{	ext{Molar mass of } AgBr} 	imes \frac{	ext{Mass of } AgBr}{	ext{Mass of organic compound}} 	imes 100$ Given: Mass of organic compound = $0.15 \ g$ Mass of $AgBr$ = $0.12 \ g$ Atomic mass of $Br = 80 \ g/mol$ Molar mass of $AgBr = 108 + 80 = 188 \ g/mol$ Substituting the values: $\% \ Br = \frac{80 	imes 0.12 	imes 100}{188 	imes 0.15}$ $\% \ Br = \frac{960}{28.2} \approx 34.04 \%$

In the Carius method for the estimation of halogens,$0.15 \ g$ of an organic compound gave $0.12 \ g$ of $AgBr$. Find out the percentage of bromine in the compound.

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