In case of nitrogen,NCl_3 is possible but not | vedclass

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Question

(A) Nitrogen $(N)$ has the electronic configuration $1s^2 2s^2 2p^3$. It lacks vacant $d$-orbitals in its valence shell,so it cannot expand its octet

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Availability of vacant $d$-orbital in $P$ but not in $N$

Vedclass · Answer

(A) Nitrogen $(N)$ has the electronic configuration $1s^2 2s^2 2p^3$. It lacks vacant $d$-orbitals in its valence shell,so it cannot expand its octet to form $NCl_5$.Phosphorus $(P)$ has the electronic configuration $[Ne] 3s^2 3p^3 3d^0$. Due to the presence of vacant $3d$-orbitals,phosphorus can expand its octet and form $PCl_5$ by promoting an electron from the $3s$ orbital to the $3d$ orbital.Therefore,the correct reason is the availability of vacant $d$-orbitals in $P$ but not in $N$.

In case of nitrogen,$NCl_3$ is possible but not $NCl_5$,while in case of phosphorus,$PCl_3$ as well as $PCl_5$ are possible. This is due to:

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