In class XI of a school,40% of the students s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $A$ be the event that the selected student studies Mathematics and $B$ be the event that the selected student studies Biology.Given:$P(A) = 40

Vedclass · Accepted Answer

$0.6$

Vedclass · Answer

(A) Let $A$ be the event that the selected student studies Mathematics and $B$ be the event that the selected student studies Biology.Given:$P(A) = 40\% = \frac{40}{100} = 0.4$$P(B) = 30\% = \frac{30}{100} = 0.3$$P(A \cap B) = 10\% = \frac{10}{100} = 0.1$We need to find the probability that the student studies Mathematics or Biology,which is $P(A \cup B)$.Using the addition theorem of probability:$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$P(A \cup B) = 0.4 + 0.3 - 0.1$$P(A \cup B) = 0.6$Thus,the probability that the selected student studies Mathematics or Biology is $0.6$.

In class $XI$ of a school,$40\%$ of the students study Mathematics and $30\%$ study Biology. $10\%$ of the class study both Mathematics and Biology. If a student is selected at random from the class,find the probability that they will be studying Mathematics or Biology.

Similar Questions

If $P(A \cup B) = \frac{2}{3}$,$P(A \cap B) = \frac{1}{6}$,and $P(A) = \frac{1}{3}$,then which of the following is true?

If a number is selected from the first $30$ natural numbers, then the probability that the number selected is divisible by $4$ or $7$ is:

If $A$ and $B$ are two independent events,then $P(A \cup B) = $

The odds against solving a problem by $A$ and $B$ are $3:2$ and $2:1$ respectively. The probability that the problem will be solved is:

The probabilities of three mutually exclusive events are $\frac{2}{3}$,$\frac{1}{4}$,and $\frac{1}{6}$. The statement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module