In a dihybrid cross,out of 16 plants obtained | vedclass

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(B) In a dihybrid cross,we consider two pairs of contrasting traits (e.g.,$AaBb 	imes AaBb$).The number of genotypes in the $F_2$ generation can be c

Vedclass · Accepted Answer

$9$

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(B) In a dihybrid cross,we consider two pairs of contrasting traits (e.g.,$AaBb 	imes AaBb$).The number of genotypes in the $F_2$ generation can be calculated using the formula $3^n$,where $n$ is the number of gene pairs involved.For a dihybrid cross,$n = 2$.Therefore,the number of genotypes = $3^2 = 9$.The $9$ genotypes are: $AABB$ $(1)$,$AABb$ $(2)$,$AaBB$ $(2)$,$AaBb$ $(4)$,$AAbb$ $(1)$,$Aabb$ $(2)$,$aaBB$ $(1)$,$aaBb$ $(2)$,and $aabb$ $(1)$.

In a dihybrid cross,out of $16$ plants obtained in the $F_2$ generation,the number of distinct genotypes is:

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