In the nuclear equation _{11}Na^{23} + _{1}H^ | vedclass

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(A) To balance the nuclear equation,we must conserve the mass number and the atomic number on both sides.Left side: Total mass number = $23 + 1 = 24$.

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(A) To balance the nuclear equation,we must conserve the mass number and the atomic number on both sides.Left side: Total mass number = $23 + 1 = 24$. Total atomic number = $11 + 1 = 12$.Right side: Mass number of $Mg = 23$. Atomic number of $Mg = 12$.Let $x$ be $_{Z}A^{A}$. Then $23 + A = 24 \implies A = 1$ and $12 + Z = 12 \implies Z = 0$.The particle with mass number $1$ and atomic number $0$ is a neutron,represented as $_{0}n^{1}$.

In the nuclear equation $_{11}Na^{23} + _{1}H^{1} \to _{12}Mg^{23} + x$,what does $x$ represent?

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