In the given circuit,find the value of V. (in | vedclass

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(B) To find the equivalent resistance of the circuit,we first simplify the network. Let the nodes be labeled as shown in the solution image. The resis

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$80$

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(B) To find the equivalent resistance of the circuit,we first simplify the network. Let the nodes be labeled as shown in the solution image. The resistors $20 \ \Omega$,$100 \ \Omega$,and $25 \ \Omega$ are connected in parallel between nodes $a$ and $b$. The equivalent resistance $R_p$ of these three resistors is given by: $\frac{1}{R_p} = \frac{1}{20} + \frac{1}{100} + \frac{1}{25} = \frac{5 + 1 + 4}{100} = \frac{10}{100} = \frac{1}{10} \ \Omega^{-1}$. Therefore,$R_p = 10 \ \Omega$. Now,the circuit consists of a $4 \ \Omega$ resistor in series with the parallel combination $R_p = 10 \ \Omega$,and a $6 \ \Omega$ resistor,all in series. The total equivalent resistance $R_{eq}$ is: $R_{eq} = 4 \ \Omega + 10 \ \Omega + 6 \ \Omega = 20 \ \Omega$. Given the total current $I = 4 \ A$,the voltage $V$ is: $V = I 	imes R_{eq} = 4 \ A 	imes 20 \ \Omega = 80 \ V$.

In the given circuit,find the value of $V$. (in $V$)

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