In the given reaction,the end product (C) is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The reaction starts with aniline $(C_6H_5NH_2)$.$2$. Treatment with $NaNO_2 + HCl$ at $0-5^{\circ}C$ performs diazotization to form benzene d

Vedclass · Accepted Answer

Benzoic acid

Vedclass · Answer

(B) $1$. The reaction starts with aniline $(C_6H_5NH_2)$.$2$. Treatment with $NaNO_2 + HCl$ at $0-5^{\circ}C$ performs diazotization to form benzene diazonium chloride $(A)$,which is $C_6H_5N_2^+Cl^-$.$3$. Reaction of $A$ with $CuCN/KCN$ (Sandmeyer reaction) replaces the diazonium group with a cyano group to form benzonitrile $(B)$,which is $C_6H_5CN$.$4$. Acidic hydrolysis of benzonitrile $(B)$ with $H_2O/H^+$ converts the cyano group $(-CN)$ into a carboxylic acid group $(-COOH)$,resulting in benzoic acid $(C)$,which is $C_6H_5COOH$.

In the given reaction,the end product $(C)$ is:

Similar Questions

$C_3H_9N$ represents

The most reactive amine towards dilute hydrochloric acid is ..........

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

What is the total number of possible amines (excluding stereoisomers) for the molecular formula $C_3H_9N$?

What is the major product of the following reaction? $C_2H_5-CONH_2$ $\xrightarrow{Br_2 / KOH} A$ $\xrightarrow{CHCl_3 / KOH} \text{Major Product}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module