In half wave rectification,if the input frequency is $60\,Hz$,then the output frequency would be $\dots\dots\dots\,Hz$.

In a full-wave $P-N$ junction diode rectifier, a load resistance of $1500 \ \Omega$ is used. No filter is used. Assume each diode has a forward resistance $R_f = 10 \ \Omega$ and reverse resistance $R_r = \infty$. When a sinusoidal voltage with a peak amplitude of $30 \ V$ and frequency $50 \ Hz$ is applied, calculate the $D.C.$ power output and $A.C.$ power input respectively.

$A$ sinusoidal voltage of peak value $200\,V$ is connected to a diode and resistor $R$ in the circuit shown,so that half-wave rectification occurs. If the forward resistance of the diode is negligible compared to $R$,the rms value of voltage across $R$ is approximately (in volt):

The figure below shows a circuit and its input voltage $V_i$ as a function of time $t$. Assuming the diodes to be ideal,which of the following graphs depicts the output voltage $V_o$ as a function of time $t$?

For the circuit shown in the figure,what will be the voltage waveform across the diode? Assume the diode is ideal.

The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without a filter is $10 \ V$. The $dc$ component of the output voltage is: