In Heisenberg's uncertainty equation $\Delta x \times \Delta p \ge \frac{h}{4\pi}$,$\Delta p$ stands for:

  • A
    Uncertainty in energy
  • B
    Uncertainty in velocity
  • C
    Uncertainty in momentum
  • D
    Uncertainty in mass

Explore More

Similar Questions

Assertion : It is impossible to determine the exact position and exact momentum of an electron simultaneously.
Reason : The path of an electron in an atom is clearly defined.

The uncertainty in the position of an electron and a helium atom is the same. If the uncertainty in the momentum of the electron is $32 \times 10^5$,then the uncertainty in the momentum of the helium atom is:

Uncertainty in the position of an electron (mass $= 9.1 \times 10^{-31} \ kg$) moving with a velocity $300 \ ms^{-1}$,accurate up to $0.001\%$ will be:

The position of both an electron and a helium atom is known within $1.0 \, nm$ and the momentum of the electron is known within $50 \times 10^{-26} \, kg \, m \, s^{-1}$. The minimum uncertainty in the measurement of the momentum of the helium atom is

An electron has a velocity of $600 \, m/s$ with an accuracy of $0.005 \%$. Calculate the uncertainty in the position of this electron.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo