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(B) The centripetal acceleration $a$ of an electron moving in a circular orbit is given by the formula:$a = \frac{v^{2}}{r}$Given values:Velocity $v =

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$9 	imes 10^{22} \; m/s^{2}$

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(B) The centripetal acceleration $a$ of an electron moving in a circular orbit is given by the formula:$a = \frac{v^{2}}{r}$Given values:Velocity $v = 2.18 	imes 10^{6} \; m/s$Radius $r = 0.528 \; \mathring{A} = 0.528 	imes 10^{-10} \; m$Substituting these values into the formula:$a = \frac{(2.18 	imes 10^{6})^{2}}{0.528 	imes 10^{-10}}$$a = \frac{4.7524 	imes 10^{12}}{0.528 	imes 10^{-10}}$$a \approx 9 	imes 10^{22} \; m/s^{2}$

In a hydrogen atom,the electron is moving around the nucleus with a velocity of $2.18 \times 10^{6} \; m/s$ in an orbit of radius $0.528 \; \mathring{A}$. The acceleration of the electron is:

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