In laboratory burners,we use
- AProducer gas
- BOil gas
- CGobar gas
- DCoal gas
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In the hydrocarbon,$CH_3(1) - CH(2) = CH(3) - CH_2(4) - C(5) \equiv CH(6)$,the state of hybridization of carbons $1, 3$ and $5$ are in the following sequence:
MediumAIPMT 2008
View SolutionDehydration of the above compound will give
Medium
View SolutionProduct $(A)$ is
Medium
View SolutionTo carry out the given conversions,select the correct option.
Difficult
View SolutionIdentify the product $(C)$ in the following reaction sequence:
$CH_3-CH(Cl)-CH(Cl)-COO^-$ $\xrightarrow{-CO_2} A$ $\xrightarrow{HCl} B$ $\xrightarrow{aq. KOH} C$
$CH_3-CH(Cl)-CH(Cl)-COO^-$ $\xrightarrow{-CO_2} A$ $\xrightarrow{HCl} B$ $\xrightarrow{aq. KOH} C$
Medium
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