In making an alloy,a substance of specific gr | vedclass

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(C) The specific gravity of a substance is defined as the ratio of its density to the density of water,i.e.,$s = \frac{\rho}{\rho_w}$.Therefore,the de

Vedclass · Accepted Answer

$\frac{m_1 + m_2}{\left( \frac{m_1}{s_1} + \frac{m_2}{s_2} \right)}$

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(C) The specific gravity of a substance is defined as the ratio of its density to the density of water,i.e.,$s = \frac{ho}{ho_w}$.Therefore,the density of the substance is $ho = s 	imes ho_w$.The total mass of the alloy is $M = m_1 + m_2$.The total volume of the alloy is $V = V_1 + V_2 = \frac{m_1}{ho_1} + \frac{m_2}{ho_2} = \frac{m_1}{s_1 ho_w} + \frac{m_2}{s_2 ho_w} = \frac{1}{ho_w} \left( \frac{m_1}{s_1} + \frac{m_2}{s_2} ight)$.The density of the alloy is $ho_{alloy} = \frac{M}{V} = \frac{m_1 + m_2}{\frac{1}{ho_w} \left( \frac{m_1}{s_1} + \frac{m_2}{s_2} ight)}$.The specific gravity of the alloy is $s_{alloy} = \frac{ho_{alloy}}{ho_w} = \frac{m_1 + m_2}{\frac{m_1}{s_1} + \frac{m_2}{s_2}}$.

In making an alloy,a substance of specific gravity $s_1$ and mass $m_1$ is mixed with another substance of specific gravity $s_2$ and mass $m_2$; then the specific gravity of the alloy is

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